This page presents the geographical name data for Schokalsky Bay in Antarctica, as supplied by the US military intelligence in electronic format, including the geographic coordinates and place name in various forms, latin, roman and native characters, and its location in its respective country's administrative division.
Feature Name (see definition): Schokalsky Bay
Feature Class (see definition): Bay
Country Code (see definition): AQ (Antarctica)
Feature ID (see definition): 13403
Primary Latitude in degrees, minutes, and seconds (see definition):
69° 15' 00" S
Primary Longitude in degrees, minutes, and seconds (see definition):
069° 55' 00" W
Primary Latitude in decimal degrees (see definition): -69.25
Primary Longitude in decimal degrees (see definition): -69.9166667
Elevation (see definition): No data
Decision Year (see definition): 01/01/1955
Description (see definition): Bay, 9 mi wide at its entrance and indenting 6 mi between Mount Calais and Cape Brown along the E coast of Alexander Island. Hampton Glacier discharges tremendous amounts of ice into the head of Schokalsky Bay at a steep gradient causing the ice there to be extremely broken and irregular, and discourages use of this bay and glacier as an inland sledging route onto NE Alexander Island. First sighted from a distance in 1909 and roughly charted by the French Antarctic Expedition (FrAE) under Charcot who, thinking it to be a strait, gave the name "Detroit Schokalsky" after Yuliy M. Shokal'skiy, Russian geographer, meteorologist and oceanographer. Charcot followed the spelling Schokalsky used by the man himself when writing in Roman script. The coast in this vicinity was photographed from the air and this bay roughly charted in 1937 by the British Graham Land Expedition (BGLE), but Charcot's "Detroit Schokalsky" was not identified. Surveys by Falklands Islands Dependencies Survey (FIDS) in 1948 identified this bay as the feature originally named by Charcot.
Date Created (see definition): No data
Date Edited (see definition): No data